3x^2+7-7=55-7x=

Solution for 3x^2+7-7=55-7x= equation:

3x^2+7-7=55-7x=

We move all terms to the left:

3x^2+7-7-(55-7x)=0

We add all the numbers together, and all the variables

3x^2-(-7x+55)+7-7=0

We add all the numbers together, and all the variables

3x^2-(-7x+55)=0

We get rid of parentheses

3x^2+7x-55=0

a = 3; b = 7; c = -55;
Δ = b2-4ac
Δ = 72-4·3·(-55)
Δ = 709
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{709}}{2*3}=\frac{-7-\sqrt{709}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{709}}{2*3}=\frac{-7+\sqrt{709}}{6}
$